Question

Threshold frequency of a certain metal for photo-electric emission is $5\times {10}^{14}$Hz. Calculate its work function.

Answer 1

Given: $v_0=5\times {10}^{14}$Hz.
Let the work function be $\omega$
We know, $\omega =hv$
$=6.6\times {10}^{-34}\times 5\times {10}^{14}$
$=3.3\times {10}^{-19}$J.