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Applications (Word Problem)

Thrice a numb...

Question

Question 97

Thrice a number decreased by 5 exceeds twice the number by 1. Find the number.

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Solution

Let the number be x. Then, thrice of this number = 3x and twice of this number = 2x.
If we decrease thrice of x by 5, we get (3x - 5).
According to the question,
(3x - 5) - (2x) = 1
$\Rightarrow 3 x - 5 - 2 x = 1 \Rightarrow x - 5 = 1 \Rightarrow x = 1 + 5 [t r a n s p o s i n g (- 5) t o R H S] \Rightarrow x = 6$
Hence, the required number is 6.

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Applications (Word Problem)

Standard VII Mathematics

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