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Question

Through the use of theorems on logarithms logab+logbc+logcd−logaydx shall be reduced to:

A
logyx
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B
logxy
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C
1
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D
0
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E
loga2yd2x
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Solution

The correct option is B logxy
We know the properties that:
loglm=log(l)log(m) and log(lm)=log(l)+log(m)............[1].

Using these properties we can reduce the given function as:
logab+logbc+logcdlogaydx

=log(a)log(b)+log(b)log(c)+log(c)log(d)log(a)log(y)+log(d)+log(x)

=log(x)log(y)=logxy.



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