Question

Tick (✓) the correct answer:
The dimensions of a room are (10 m × 8 m × 3.3 m). How many men can be accommodated in this room if each man requires 3 m³ of space?
(a) 99
(b) 88
(c) 77
(d) 75

Answer 1

(b) 88

Volume of the room$=10\times 8\times 3.3=264m^3$
One person requires 3 m³.
∴ Total no. of people that can be accommodated$=\frac{264}{3}=88$