Question

tiles of length 75 cm and breadth 60 cm are used to make the flooring of a house. How many such tiles are required if the floor is 120 m long and 22.5 m wide ?

Answer 1

$$\begin{gathered} \mathrm{Area}\mathrm{of}\mathrm{the}\mathrm{floor}=\left(120\mathrm{m}\right)\times \left(22.5\mathrm{m}\right)=2700{\mathrm{m}}^2 \\ \mathrm{Area}\mathrm{of}\mathrm{one}\mathrm{tile}=\left(\frac{75}{100}\mathrm{m}\right)\times \left(\frac{60}{100}\mathrm{m}\right)=\frac{4500}{10000}{\mathrm{m}}^2=0.45{\mathrm{m}}^2 \\ \mathrm{Number}\mathrm{of}\mathrm{tiles}\mathrm{required}=\frac{2700}{0.45}=\frac{2700\times 100}{45}=6000 \end{gathered}$$