Tin is obtained from cassiterite by reduction with coke- Use the data given below to determine the minimum temperature in K at which the reduction of cassiterite by coke would take place-At 298 K-fH-SnO2s-581-0 kJmol-1-fH-CO2g-394-0 kJmol-1S-SnO2s- 56-0 JK-1mol-1- S-Sns- 52-0 JK-1mol-1- S-Cs- 6-0 JK-1mol-1- S-CO2g- 210-0 JK-1mol-1Assume that the enthalpies and the entropies are temperature independent-

SnO_2(s) + C(s) → CO_2 + Sn ΔH = (Δ_fH)_P nbsp;(Δ_fH)_R nbsp; = (– 394 + 581) kJ/mol = + 187 kJ/mol ΔS = (S)_P (S)_R = (210 + 52) – (56 + nbsp;6) ...

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Byju's Answer

Standard XII

Chemistry

Internal Energy

Tin is obtain...

Question

Tin is obtained from cassiterite by reduction with coke. Use the data given below to determine the minimum temperature (in K) at which the reduction of cassiterite by coke would take place.

At $298 K$ : $Δ_{f} H^{\circ} (S n O_{2} (s)) = - 581.0 k J m o l^{- 1}, Δ_{f} H^{\circ} (C O_{2} (g)) = - 394.0 k J m o l^{- 1}$
$S^{\circ} (S n O_{2} (s)) = 56.0 J K^{- 1} m o l^{- 1}, S^{\circ} (S n (s)) = 52.0 J K^{- 1} m o l^{- 1}, S^{\circ} (C (s)) = 6.0 J K^{- 1} m o l^{- 1}, S^{\circ} (C O_{2} (g)) = 210.0 J K^{- 1} m o l^{- 1}$
Assume that the enthalpies and the entropies are temperature independent.

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Solution

$S n O_{2} (s) + C (s) \to C O_{2} + S n$
$Δ H = (Δ_{f} H)_{P} - (Δ_{f} H)_{R}$
$= (- 394 + 581) k J / m o l$
$= + 187 k J / m o l$

$Δ S = (S)_{P} - (S)_{R}$
$= (210 + 52) - (56 + 6) J / K m o l$

$= 200 J / k m o l$

For any reaction to take place, $Δ G < 0$
The minimum temperature is where $Δ G = 0$
$Δ G = 0 = Δ H - T Δ S$
$187 \times 1000 - 200 T = 0$

$T = 935 K$

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Calculate $△ G^{⊖}$ for the following reaction:
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Given,
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