Question

Titanium shows magnetic moment of 1.73 BM in its compound. What is the oxidation state of titanium in the compound?

• A. 2
• B. 1
• C. 3
• D. 4

Answer 1

The correct option is C 3

As $\mu =\sqrt{n(n+2)}B.Mn=$ no. of unpaired electrons and here, $\mu =1.73$ i.e. one unpaired electron, electronic configuration of $Ti(E.C.)=[Ar{]}^{18}3d^2,4s^2$, so it will lose three electrons to have one unpaired electron and thus the oxidation state of titanium is +3.