Titanium shows magnetic moment of $1.73 B M$ ; then find out its oxidation state:

+ 1

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+ 4

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+ 3

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+ 2

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Solution

The correct option is C $+ 3$
$1.73 B M$ $= \sqrt{n \times (n + 2)}$ .

Solving this we get n $=$ 1.

So Titanium has a electron configuration of [Ar] $4 s^{0} 3 d^{1}$ . So its oxidation state is +3.

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