To 50ml of a HCl solution, 25ml of 0.5N Na2CO3 solution is added. The remaining acid required 20cc of 0.5N NaOH solution for complete neutralization. The normality of the acid solution is
A
0.9N
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B
0.45N
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C
0.225N
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D
1.45N
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Solution
The correct option is B0.45N Milliequivalents of acid = Milliequivalents of Na2CO3 + Milliequivalents of NaOH 50×N=(25×0.5)+(20×0.5) N = 0.45N