Question

To a $10\text{mL}$ of ${10}^{-3}N{H}_{2}S{O}_4$ solution water has been added to make the total volume of one litre. Its $pOH$ would be:

• A. $3$
• B. $5$
• C. $9$
• D. $9.3$

Answer 1

The correct option is C $9$

By using the relation,
$N_1{V}_1=N_2{V}_2$
${10}^{-3}\times 10=N_2\times 1000$
$\Rightarrow N_2={10}^{-5}$
$\therefore pH=5$
$\Rightarrow pOH=14-5=9$.