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Question

To access gate C, simplify the expression:
[(14÷2×3)+16×(77)+1614÷7+15]÷2×10



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Solution

In the given expression, there are multiple parentheses. Hence we go for the innermost parentheses.

While evaluating the expression inside parentheses, we follow the PEMDAS rule.

[(14÷2×3)+16×(77)+1614÷7+15]÷2×10
=[(7×3)+16×(77)+1614÷7+15]÷2×10
=[21+16×(77)+1614÷7+15]÷2×10

We move to the following innermost parentheses expression.

[21+16×(77)+1614÷7+15]÷2×10
=[21+16×0+1614÷7+15]÷2×10

Now, the square brackets have multiple operations.
Hence, we follow the PEMDAS rule to solve the expression inside it.

[21+16×0+1614÷7+15]÷2×10
=[21+0+1614÷7+15]÷2×10
=[21+0+162+15]÷2×10

Now the expression inside square brackets has addition operations. We move from left to right.

[21+0+162+15]÷2×10
=[21+162+15]÷2×10
=[372+15]÷2×10
=[35+15]÷2×10
=50÷2×10

Now the resulting expression has only multiplication and division operations.

50÷2×10
=25×10
=250

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