Question

To construct a triangle similar to a given $\Delta ABC$ with its sides $\frac{7}{4}$ of the corresponding sides of $\Delta ABC$, first draw a ray BX such that $\angle CBX$ is an acute angle and X lies on the opposite side of A with respect to BC. Then, locate points $B_1,B_2,B_3,\dots \dots$ on BX at equal distances and next step is to join the points

• A. $B_{4}toC$
• B. $B_{7}toC$
• C. $B_{3}toC$
• D. $B_{11}toC$

Answer 1

The correct option is A $B_{4}toC$

Given a triangle ABC, we are required to construct a triangle whose sides are $\frac{7}{4}$ of the corresponding sides of triangle ABC.

Steps of construction:
1.Draw any ray BX making an acute angle with BC on the side opposite to the vertex A.
2.Locate 7 points (the greater of 7 and 4 in $\frac{7}{4})B_1,B_2,B_3.......,B_7$ on BX so that $B{B}_1=B_1{B}_2=.......=B_6{B}_7$
3.Join $B_4(the{4}^{th}point,4$ being smaller of 7 and 4 in $\frac{7}{4})$ to C.


Hence, the correct answer is option a.