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Question

To construct a triangle similar to a given triangle ABC with its sides 6/5th of the corresponding sides of ΔABC. Correct order of steps of construction -
(a) Draw a ray AX inclined at certain angle with AB on opposite side of C.
(b) Starting from A, cut off six equal line segments AX1, X1X2, X2X3, X3X4, X4X5 and X5X6 on AX.
(c) Draw a line B'C' parallel to BC to intersect AC produced at C'
(d) Join X5B and draw a line X6B' parallel to X5B, to intersect AB produced at B'.

A
abcd
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B
acbd
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C
abdc
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D
adcb
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Solution

The correct option is C abdc
To construct a triangle like the one given in the following question, the given steps are to be followed:
1. Draw a ray AX inclined at a certain angle with AB on opposite side of C.
2. Starting from A, cut off six equal line segments AX1,X1X2,X2X3,X3X4,X4X5andX5X6 on AX.
3. Join X5B and draw a line X6B parallel to X5B, to intersect AB produced at B.
4.Draw a line BC parallel to BC to intersect AC produced at C.

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