To convert density of $k g m^{- 3}$ into $g c m^{- 3}$ , we divide quantities with

100

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200

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1000

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Solution

The correct option is D 1000
$1$ $\frac{k g}{m^{3}} = 1 \times 1000$ $g \times \frac{1}{10^{6} (c m)^{3}} = \frac{1}{1000}$ $\frac{g}{c m^{3}}$

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