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Question

To determine the radii of a univalent ion, Pauling gave a method as follows:
i. In an ionic crystal of the type M+X, cations and anions are in contact with each other. Therefore, the sum of their ionic radius is equal to the interionic distance.
ii. r+M+rX=cZeff(M+)+cZeff(X)pm Zeff is the effective nuclear charge Zeff=Zσ ; where σ is the screening constant.
For Ne,σ=4.5
r+M=cZeff(M+) and rX=CZeff(X)

In NaF crystal,r+Na+rF=230 pm therefore, the radius of F is

A
136 pm
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B
94.5 pm
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C
112 pm
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D
115 pm
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Solution

The correct option is A 136 pm
r+M+rX=cZeff(M+)+cZeff(X)pm
230=c(114.5)+c(94.5) pm
230=11c(6.5×4.5) pm
c=6.5×4.5×23011 pm
rF=6.5×4.5×23011×14.5
rF=136 pm

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