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Question

# Question 3 To divide a line segment AB in the ratio 5:6, draw AX such that ∠ BAX is an acute angle, the draw a ray by parallel to AX and the points A1,A2,A3... and B1,B2,B3... are located to equal distances on ray AX and BY, respectively. Then, the points joined are (A) A5 and B6 (B) A6 and B5​​​​​​​ (C) A4 and B5​​​​​​​ (D) A5 and B4​​​​​​​

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Solution

## Given, a line segment AB and we have to divide it in the ratio 5 : 6 Steps of constructions Draw a ray AX making an acute ∠BAX Draw a ray By parallel to AX by making ∠ABY equal to ∠BAX. Now locate the points A1,A2,A3,A4 and A5 ( m = 5 ) on AX and B1,B2,B3,B4,B5 and B6 (n=6) such that all the points are at equal distance from each other. Join B6A5 let it intersect AB at a point C. Then AC : BC = 5 : 6

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