To divide a line segment AB in the ratio p:q (p,q are positive integers), draw a ray AX so that ∠BAX is an acute angle and then mark points on ray AX at equal distances such that the minimum number of these points is:
A
Greater of p and q
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B
p+q
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C
p+q−1
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D
pq
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Solution
The correct option is Cp+q From the figure, we can see that the total number of equidistant points to be drawn on Ray AX is p+q.