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Standard XII

Physics

Mixed Combination of Cells

To get maximu...

Question

To get maximum current in a resistance of $3 Ω$ one can use n rows of m cells connected in parallel. If the total no. of cells is 24 and the internal resistance of a cell is $0.5 Ω$ then

m = 12, n = 2

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m = 8, n = 4

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m = 2, n = 12

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m = 6, n = 4

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Solution

The correct option is A m = 12, n = 2
In this question $R = 3 Ω, m n = 24, r = 0.5 Ω$ and $R = \frac{m r}{n}$ . On putting the values we get n = 2 and m = 12.

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To get maximum current in a resistance of 3Ω one can use n rows of m cells connected in parallel. If the total no. of cells is 24 and the internal resistance of a cell is0.5Ω then

The correct option is A m = 12, n = 2In this question R=3Ω,mn=24,r=0.5Ω and R=mrn. On putting the values we get n = 2 and m = 12.

To get maximum current in a resistance of $3 Ω$ one can use n rows of m cells connected in parallel. If the total no. of cells is 24 and the internal resistance of a cell is $0.5 Ω$ then

The correct option is A m = 12, n = 2
In this question $R = 3 Ω, m n = 24, r = 0.5 Ω$ and $R = \frac{m r}{n}$ . On putting the values we get n = 2 and m = 12.