Question

To metallic strips of different metals are riveted together to form a composite metallic strip of thickness 0.1 cm. If the strip is heated to 100^oC, what will be the radius of curvature of the strip? Given, the values of a of the two metals are 18* 10^{-6 o}C^-1 and 12*10^{-6 o}C^-1

Answer 1

Dear Student

Radius of curvature of bimetallic strip when subjected to change in temperature can be given as
$$\begin{gathered} R=\frac{t}{\left({\alpha }_2-{\alpha }_1\right)∆T} \\ tisthicknessofstrip \\ {\alpha }_{1}and{\alpha }_{2}arelinearthermalexpansioncoefficientsofstrips{\alpha }_2>{\alpha }_1 \\ ∆TISCHANGEINTEMPERATURE \\ R=\frac{t}{\left({\alpha }_2-{\alpha }_1\right)∆T}=\frac{0.1\times {10}^{-2}m}{\left(18\times {10}^{-6}-12\times {10}^{-6}\right)100}=0.0166\times {10}^2=1.66m \end{gathered}$$

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