To neutralise completely $20 m L$ of $0.1 M$ aqueous solution of phosphorous acid $(H_{3} {P O}_{3}$ ), the volume of $0.1 M$ aqueous $K O H$ solution required is

20 m L

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30 m L

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40 m L

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50 m L

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Solution

The correct option is C $40 m L$
$N_{1} V_{1} (a c i d) = N_{2} V_{2} (b a s e)$

$H_{3} {P O}_{3}$ is a dibasic acid
Hence, $0.1 \times 2 \times 20 = 0.1 \times 1 \times V_{2}$

$V_{2} = \frac{0.1 \times 2 \times 20}{0.1 \times 1} = 40 m L$

Hence, option $C$ is correct.

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Similar questions

To neutralise completely 20 ml of 0.1 M of aqueous solution of phosphoric acid the volume of 0.1 M aqueous KOH solution required is ??

To neutralize completely 20 ml of 0.1 M aqueous solution of $H_{3} P O_{3}$ , the volume of 0.1 M aqueous KOH solution required is:

To neutralize completely 20 mL of 0.1molar aqueous of H₃PO₄,what volume of 0.1M KOH solution will be required?

40 m L

0.1 M

20 m L

0.3 M

K_{b}

1.8 \times 10^{- 5}

(H_{3} P O_{3})

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