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Byju's Answer
Standard XII
Chemistry
Orbitals
To place the ...
Question
To place the lab in the first orbit.
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Solution
Energy of lab in an orbit is
E
=
1
2
m
(
√
G
M
r
)
2
−
G
M
m
r
=
−
G
M
m
2
r
Hence, energy required would be equal to the change i total energy,
Δ
E
=
−
G
M
m
2
(
2
R
)
+
G
M
m
R
=
3
G
M
m
4
R
=
3
4
g
m
R
=
0.75
×
9.8
×
2000
×
6400000
=
9.6
×
10
10
J
Answer is
9.6
×
10
10
J
.
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