Question

Today Rebecca, who is 34 years old, and her daughter, who is 8 years old, celebrate their birthdays. How many years will pass before Rebecca's age is twice her daughter's age?

• A. 10
• B. 14
• C. 18
• D. 22
• E. 26

Answer 1

Answer: (C)

18

Let Rebecca's age be $R$.

Her daughters age be $D$.

Let say $x$ years have passed

$\therefore R=34+x$

$d=8+x$

Given $34+x=2(8+x)$

$34+x=16+2x$

$18=x$

$\therefore 18$ years have passed