Top surface of a table is a trapezium in shape as shown in the figure alongside. Find its area if its parallel sides are $1.5 m$ and $2 m$ and the perpendicular distance between them is $1.2 m$ .

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Solution

Area of trapezium $= (\frac{a + b}{2}) \times h$
$h = 1.2 m$ ; $a = 2 m$ ; $b = 1.5$ m
$(\frac{2 + 1.5}{2}) \times 1.2 = 2.1 m^{2}$ .

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Top surface of a table is a trapezium in shape as shown in the figure alongside. Find its area if its parallel sides are 1.5m and 2m and the perpendicular distance between them is 1.2m.

Area of trapezium=(a+b2)×hh=1.2m; a=2m; b=1.5m(2+1.52)×1.2=2.1m2.

Top surface of a table is a trapezium in shape as shown in the figure alongside. Find its area if its parallel sides are $1.5 m$ and $2 m$ and the perpendicular distance between them is $1.2 m$ .

Area of trapezium $= (\frac{a + b}{2}) \times h$
$h = 1.2 m$ ; $a = 2 m$ ; $b = 1.5$ m
$(\frac{2 + 1.5}{2}) \times 1.2 = 2.1 m^{2}$ .