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F=ma

Top view of a...

Question

Top view of a block on a table is shown $(g = 10 m / s^{2})$
Find out the acceleration of the block.

0.6

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0.8

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1.6

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0.5

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Solution

The correct option is A $0.6$
Now $f_{s} \leq μ N$
$∴ f_{s} \leq 50$
$F_{R} > f_{s m a x}$
Hence the block will move
$a = \frac{F_{R} - f_{s m a x}}{m}$

$a = \frac{56 - 50}{10} = 0.6 m / s^{2}$

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