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Question

Torque of a force F=2^i+3^j acting at a point (1m,0,3m) about Z axis is :

A
3 Nm
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B
130 Nm
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C
6 Nm
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D
0 Nm
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Solution

The correct option is D 3 Nm
Torque about (0,0,0)
=¯rׯF
=(^i+3^k)×(2^i+3^j)
=3^k+6(+^j)+9(^i)
TorqueaboutZaxis=coefficientof^k
=3 Nm

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