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Question

Total number of electrons present in 48g Mg 2+ are:

A
24 NA
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B
2 NA
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C
20 NA
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D
None of these
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Solution

The correct option is A 20 NA
24 gm of Magnesium contains=NA atoms. Where NA= 6.023 × 1023

48 gm of Mg contains =2NA atoms.

1 atom of Mg contains 12 electrons

Mg2+ ion will contain (122)=10 electrons

2NA Mg2+ ions will contain

=10×2NA electrons

=10×2×6.023×1023

=20NA

Hence, the correct option is (C).

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