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Geometrical Isomerism in Square Planar Geometry

Total number ...

Question

Total number of geometrical isomers for the complex $[R h C l (C O) (P P h_{3}) (N H_{3})]$ is:

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Solution

Total number of geometrical isomers for the complex $[R h C l (C O) (P P h_{3}) (N H_{3})]$ is $^{'} 3^{'}$ , since it is a square planar.

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