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Question

Total number of six-digit numbers that can be formed having the property that every succeeding digit is greater than the preceding digit is equal to

A
9C3
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B
10C3
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C
9P3
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D
10P3
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Solution

The correct option is C 9C3
x1<x2<x3<x4<x5<x6, when the number is x1x2x3x4x5x6.
Clearly
No digit can be zero. Also, all the digits are distinct. So selection of six digits from the list of digits 1,2,3,4,5,6,7,9 can be done in 9C6=9C3 ways.

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