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Electronegativity and Hybridisation

Total number ...

Question

Total number of sp hybridised atoms present in the given compound is CH2 = CH – C ≡ C — CN

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Q. In the following compound, the number of sp hybridised carbons are:

\begin{matrix} C H_{2} = C = C H & - & C H & - & C & \equiv & C H | C N \end{matrix}

s p^{2}

and sp-hybridised carbon atoms are present respectively in the following compound?

C_{2}

C_{3}

C H \equiv C - C H = C H_{2}

are respectively

s p

s p^{2}

The bond between carbon atom (1) and carbon atom (2) in compound $N \equiv C - C H = C H_{2}$ involves the hybridised carbon as?

Q. In the compound,

6 C H_{2} = 5 C H - 4 C H_{2} - 3 C H_{2} - 2 C H \equiv 1 C H_{2}

C_{2} - C_{3}

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Electronegativity and Hybridisation

Standard XII Chemistry

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