Question

$△ABC\sim △DEF$. Their areas are $64{cm}^2$ and $121{cm}^2$.
Then ratio of corresponding sides $=$

Answer 1

Given that:

$△ABC\sim △DEF$

$A\left(△ABC\right)=64c{m}^2,A\left(△DEF\right)=121c{m}^2$

Solution:
We know that,

$\frac{A\left(△ABC\right)}{A\left(△DEF\right)}=\frac{A{B}^2}{D{E}^2}$

or, $\frac{A{B}^2}{D{E}^2}=\frac{64c{m}^2}{121c{m}^2}$

or, $\frac{AB}{DE}=\sqrt{\frac{64c{m}^2}{121c{m}^2}}$

or, $\frac{AB}{DE}=\frac{8}{11}$

Therefore, ratio of corresponding sides of the two triangles is $8:11.$