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Question

H and S for the reaction: Ag2O(s)2Ag(s)+12O2(g) are 30.56 kJ mol1 and 66.0 J K1mol1 respectively. Calculate the temperature at which free energy change for the reaction will be zero. Predict whether the forward reaction will be favored above or below this temperature.


A

298 K, above

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B

300 K, below

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C

373 K, above

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D

463 K, above

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Solution

The correct option is D

463 K, above


We know that, G=HTS
At equilibrium, G = 0
So that 0 = HTS
or T=HS
given that H - 30.56 kJ mol1 = 30560 J mol1
S = 66.0 J K1mol1
T = 3056066 = 463 K
Above this temperature, G will be negative and the process will be spontaneous in forward direction.


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