Triose phosphates produced in the following diagram are:

3-PGA and 2-PGA

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3-PGAL and 3-PGA

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3-PGAL and DiHAP

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3-PGA and DiHAP

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Solution

The correct option is C 3-PGAL and DiHAP

The fructose-1,6-diphosphate is split into dihydroxyacetone phosphate (DiHAP) and 3-phosphoglyceraldehyde (3-PGAL). We find that there is one step where NADH + H+ is formed from NAD+; this is when 3-phosphoglyceraldehyde (3-PGAL) is converted to 1, 3-bisphosphoglycerate (DPGA). Two redox-equivalents are removed (in the form of two hydrogen atoms) from PGAL and transferred to a molecule of NAD+.

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Similar questions

	I.		II.
$1$ .	Fructose $1, 6$ diphosphate $\to 3$ PGAL $+$ DHAP	a.	Enolase
$2$ .	Citrate $\to$ Cis - aconitate	b.	Thiokinase
$3$ .	Succinyl Co. A $\to$ Succinate	c.	Aconitase
$4$ .	$2$ PGA $\to$ PEPA	d.	Aldolase

Identify a,b $&$ c in the given figure

C O_{2}

H_{2} O

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