Question

True order of bond angle among group-16 hydrides is:

• A. $H_{2}O>H_{2}S>H_{2}Se>H_{2}Te$
• B. $H_{2}Te>H_{2}Se>H_{2}S>H_{2}O$
• C. $H_{2}S>H_{2}O>H_{2}Se>H_{2}Te$
• D. $H_{2}O>H_{2}S>H_{2}Te>H_{2}Se$

Answer 1

Answer: (A)

$H_{2}O>H_{2}S>H_{2}Se>H_{2}Te$

As we move down the group. the bond angles decrease due to decrease in bond pair-bond pair repulsion.

$H_{2}O\left({104.45}^o\right)>H_{2}S\left({92.1}^o\right)>H_{2}Se\left({91}^o\right)>H_{2}Te\left({90}^o\right)$.

all this compouds having bent shape struture.