Question

Tungsten crystallizes in body centered cubic unit cell. If the edge of the unit cell is 316.5 pm, what is the radius of tungsten atom?

Answer 1

It is a BCC, for which radius is gievn by:

$r=\frac{\sqrt{3}}{4}\times a$

a=316.5 pm

Substituting the value of a we get,

Radius=$\frac{\sqrt{3}}{4}\times 316.5$

=$137.04pm$