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Apparent Frequency

Tuning fork F...

Question

Tuning fork $F_{1}$ has a frequency of 256 Hz and it is observed to produce 6

beats/second with another tuning fork $F_{2}$ . When $F_{2}$ is loaded with wax, it

still produces 6 beats/second with $F_{1}$ . The frequency of $F_{2}$ before loading

was

[MP PET 1990]

253 Hz

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262 Hz

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250 Hz

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259 Hz

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Solution

The correct option is B
262 Hz

$n_{A}$ = Known frequency = 256 Hz, $n_{B}$ = ?

x = 6 bps , which remains the same after loading.

Unknown tuning fork $F_{2}$ is loaded so $n_{B} ↓$

Hence $n_{A} - n_{B} ↓= x$ .....(i) ---- Wrong

$n_{B} ↓ - n_{A} = x$ ....(ii) ---- correct

$\Rightarrow n_{B} = n_{A} + x = 256 + 6 = 262 H z .$

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When a tuning fork of frequency 341 is sounded with another tuning fork, six

beats per second are heard. When the second tuning fork is loaded with wax

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second. The natural frequency of the second tuning fork is

[MP PET 1989]

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