Question

Twelve resistor each of resistance 1W are connected in the circuit shown in figure. Net resistance between point A and H would be

• A. $\frac{5}{3}\Omega$
• B. $1\Omega$
• C. $\frac{7}{6}\Omega$
• D. $\frac{3}{4}\Omega$

Answer 1

The correct option is D

$\frac{3}{4}\Omega$

If we connect voltage source across A and H, then potential at C, E, F and D are same and circuit reduced as

$\frac{1}{R_{eq}}=\frac{1}{2}+\frac{1}{2}+\frac{1}{3}{R}_{eq}=\frac{3}{4}\Omega$