Question

Twice a number when decreased by $7$ gives $45$. Find the number.

Answer 1

Let the number be $x$.

Twice the number $=2x$

It is given that, Twice a number when decreased by $7$ gives $45$.

$\Rightarrow 2x-7=45$

$\Rightarrow 2x=45+7$

$\Rightarrow 2x=52$

$\Rightarrow x=\frac{52}{2}$

$\Rightarrow x=26$

hence, the required number is $26$.