Two adjacent sides of a rectangle are $3 a - b$ and $6 b - a$ , then what is its perimeter?

4 a + 10 b

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4 b + 10 a

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2 a - 5 b

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4 a - 10 b

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Solution

The correct option is B $4 a + 10 b$
Perimeter $= 2 (l + b)$

$= 2 (3 a - b + 6 b - a)$

$= 2 (5 b + 2 a)$

$= 10 b + 4 a$

Suggest Corrections

Similar questions

6 a + 9 b

8 a - 4 b

∣ ∣ ∣ ∣ \begin{matrix} a & a + b & a + b + c 2 a & 3 a + 2 b & 4 a + 3 b + 2 c 3 a & 6 a + 3 b & 10 a + 6 b + 3 a \end{matrix} ∣ ∣ ∣ ∣ = a^{3}

\frac{4 a^{2} - 8 a + 5 a b - 10 b}{4 a + 5 b} = . . . . . . . . . . . . . .

8 + 13 a + 7 a^{2}

2 a^{2} + 3 a + 2

3 a^{2} - 4 a - 1

a^{2} - 2 a + 1

3 a^{2} - 5 a + 3

6 a^{2} - 4 a + 9

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