Two aeroplanes I and II bomb a target in succession- The probabilities of I and II scoring a hit correctly are 3-10 and 1-5 respectively- The second plane will bomb only if the first misses the target- The probability that the target is hit by the second plane is

Two aeroplanes 1 and 2 bomb a target in succession.The probability of 1 and 2 scoring a hit correctly are 0.3 and 0.2 respectively. The second plane will bomb only when 1st one misses the target.The probability that the target is hit by 2nd plane is?

Q. The probability that a bomb will hit a target is

0.8

. Find the probability that out of

10

bombs dropped, exactly

2

will hit the target.

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Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 310 and 15 respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is

The correct option is B 750Probability of the event =P(Bomb I fails)×P(Bomb II suceeds)=(1−310)×15=750Hence Option B

Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are $\frac{3}{10}$ and $\frac{1}{5}$ respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is

The correct option is B $\frac{7}{50}$
Probability of the event $= P(Bomb I fails) \times P(Bomb II suceeds) = (1 - \frac{3}{10}) \times \frac{1}{5} = \frac{7}{50}$
Hence Option B