Two angels of a traiangel are equal and the third angle is grater than each one of them by $18^{\circ}$ .Find the angles.

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Solution

ANSWER:
Let ∠A=∠B and ∠C=∠A+18°.
Then,
∠A+∠B+∠C=180° ( Sum of the angles of a triangle)

∠A+∠A+∠A+18°=180°

⇒3∠A=162°

⇒∠A=54°
Since,
∠A=∠B⇒∠B=54° ∴∠C=∠A+18°
∠C=54+18°=72°

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Two angels of a traiangel are equal and the third angle is grater than each one of them by 18∘.Find the angles.

ANSWER: Let ∠A=∠B and ∠C=∠A+18°. Then, ∠A+∠B+∠C=180° ( Sum of the angles of a triangle) ∠A+∠A+∠A+18°=180° ⇒3∠A=162° ⇒∠A=54° Since, ∠A=∠B⇒∠B=54° ∴∠C=∠A+18° ∠C=54+18°=72°

Two angels of a traiangel are equal and the third angle is grater than each one of them by $18^{\circ}$ .Find the angles.

ANSWER:
Let ∠A=∠B and ∠C=∠A+18°.
Then,
∠A+∠B+∠C=180° ( Sum of the angles of a triangle)

∠A+∠A+∠A+18°=180°

⇒3∠A=162°

⇒∠A=54°
Since,
∠A=∠B⇒∠B=54° ∴∠C=∠A+18°
∠C=54+18°=72°