Question

Two angles of a hexagon are ${90}^o$ and ${10}^o$ remaining four angles are equal, find each equal angle.

Answer 1

Given : 2 angles of hexagon are ${90}^{\circ }$ and ${10}^{\circ }$

other 4 angles are equal.

To find each equal angle

Let the other 4 equal angles = $x^{\circ }$

since sum of angles of a hexagon = ${720}^{\circ }$

$\therefore {90}^{\circ }+{10}^{\circ }+4x^{\circ }={720}^{\circ }$

$4x^{\circ }={720}^{\circ }-{100}^{\circ }$

$4x^{\circ }={620}^{\circ }$

$x^{\circ }=\frac{{620}^{\circ }}{4}$

$\therefore$ such equal angle = ${155}^{\circ }$

$x={155}^{\circ }$