Question

Two balance dice are thrown once. What is the probability that the sum of numbers on two dice is:
(1) more than $10$
(2) multiple of $5$

Answer 1

$S=36$ outcomes

i) Req. results= $(5,6)(6,5)(6,6)$

$P\left(A\right)=\frac{3}{36}=\frac{1}{12}$

ii)Req. results$=(1,4)(2,3)(3,2)\left(4.1\right)(5,5)(4,6)(6,4)$

$P\left(B\right)=\frac{7}{36}$