Two balls A and B having masses 1kg and 2kg, moving with speeds 21m/s and 4m/s respectively in opposite direction, collide head on. After collision A moves with a speed of 1m/s in the same direction, the correct statements is :
A
The velocity of B after collision is 6m/s opposite to the direction of motion before collision
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B
The coefficient of restitution is 0.2
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C
The loss of kinetic energy due to collision is 200J
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D
The impulse of the force between the two balls is 40Ns
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Solution
The correct options are A The velocity of B after collision is 6m/s opposite to the direction of motion before collision C The coefficient of restitution is 0.2 D The loss of kinetic energy due to collision is 200J Using Momentum Conservation: ⇒m1u1+m2u2=m1v1+m2v2⇒1(21)+2(−4)=1(1)+2v2⇒v2=6m/s Coefficient of Restitution: e=v2−v1u1−u2=6−121+4=0.2 Kinetic Energy lost: =12m1(v21−u21)+12m2(v22−u22)=121(1−441)+122(36−16)=−200J Impulse of Force: I=(Δmv)1=1(1−21)=−20=(Δmv)2=2(6−(−4))=20