Question

Two balls are projected from a tower such that one is vertically upward with a velocity of 9 m/s and other horizontally with same speed. The relative acceleration of one ball w.r.t. other is $(g=10m/s^2)$

• A. 10 $m/s^2$
• B. 20 $m/s^2$
• C. 18 $m/s^2$
• D. $Zero$

Answer 1

The correct option is D $Zero$

Acceleration of both the balls $a_1=a_2=10xm/s^2$ (downwards)

So, relative acceleration $a_{rel}=a_1-a_2=10-10=0xm/s^2$