Two balls of masses 2kg and 4kg are moving towards each other with speeds 6m/s and 4m/s respectively, on a frictionless surface. If the coefficient of restitution is 0.5, the relative velocity of seperation between the two balls is
A
1m/s
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B
2m/s
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C
5m/s
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D
−1m/s
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Solution
The correct option is C5m/s Given,
Mass of ball 1 (m1)=2kg
Mass of ball 2 (m2)=4kg
Velocity of ball 1 (u1)=6m/s
Velocity of ball 2 (u2)=−4m/s (opposite)
Coefficient of restitution (e)=0.5
Since coefficient of restitution e=velcocity of separationvelocity of approach=v2−v1u1−u2 ⇒v2−v1=e(u1−u2) ⇒v2−v1=0.5(6−(−4)) =5m/s