Two batteries with e.m.f 12V and 13V are connected in parallel across a load resistor of 10Ω. The internal resistance of the two batteries are 1Ω and 2Ω respectively. The voltage across the load lies between
A
11.4V and 11.5V
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B
11.7V and 11.8V
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C
11.6V and 11.7V
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D
11.5V and 11.6V
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Solution
The correct option is D11.5V and 11.6V
Equivalent EMF of two cells in parallel, Eeq=[E1r1+E2r2]req Eeq=121+13211+12 =37232=373V Req=23 + 10 Ω I=37323+10=373=3732A
Voltage across load = IR=(3732)(10)=11.56V