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Question
Two billiard balls each of mass 0.05 kg moving in opposite directions with speed of 6ms−1 collide and rebound with the same speed. What is the impulse imparted to each ball due to the other ?
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Solution
m=0.05kgu1=6m/s and after rebounding v1=−6m/su2=−6m/s and after rebounding v2=6m/s
taking the first ball into consideration we get the momentum change is Δp=mΔV=m(v−u)=0.05(−6−6)=−0.6N−sso the magnitude of the impulse by each ball on another ball is 0.6Newton−sec
u1=6m/s and after rebounding v1=−6m/s
u2=−6m/s and after rebounding v2=6m/s
taking the first ball into consideration we get the momentum change is Δp=mΔV=m(v−u)=0.05(−6−6)=−0.6N−s
so the magnitude of the impulse by each ball on another ball is 0.6Newton−sec
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