Question

Two blocks A and B each of mass 1kg placed on a smooth horizontal surface.Two horizontal forces 5 N and 10 N are applied on them respectively. The block A does not slide on block B.Then the normal reaction between the two block is:

Answer 1

After the pieces come in contact the net power would be toward the10 N constrain. Along these lines, the net power will be (10 – 5 ) N = 5 N.
With some geometry, you will find that the ordinary response on the square on the left hand side by the piece on the righthand side makes a point of 60 .After both the pieces come in contact we can regard the pieces as one framework so the acceleration of both the pieces moves toward becoming F/m = 10 – 5/1 + 1 = 5/2 As the net power on the piece on the left hand side is 5 N toward the power consequently, we get the condition as takes after
N cos 60 – 5 = m a
N cos 60 – 5 = 5/2
N cos 60 = 135/2N/2 = 15/2
N = 15
Also for the other block,, the condition framed will be
10 – N cos 60 = 5/2
Settle and we get
N = 15