Question

Two blocks ${}^{\prime }{A}^{\prime }$ and ${}^{\prime }{B}^{\prime }$ each of mass ${}^{\prime }{m}^{\prime }$ are placed on a smooth horizontal surface. Two horizontal forces $F$ and $2F$ are applied on both the blocks ${}^{\prime }{A}^{\prime }$ and ${}^{\prime }{B}^{\prime }$ respectively as shown in figure. The block $A$ does not slide on block $B$. Then the normal reaction acting between the two blocks is:


Report $n$, if the answer in $nF$

Answer 1

Acceleration of two mass system is $a=\frac{F}{2m}$ leftward
FBD of block $A$
$\text{N}\cos {60}^{\circ }-F=ma=\frac{mF}{2m}$,
Solving, $\text{N}=3F$