Two blocks 'A' and 'B' each of mass 'm' are placed on a smooth horizontal surface. Two horizontal force F and 2F are applied on both the blocks 'A' and 'B' respectively as shown in figure. The block A does not slide on block B. Then the normal reaction acting between the two blocks is: (Assume no friction between blocks)
3F
Both A and B will have same acceleration. Let's assume that to be a leftwards Free Body Diagram of A
Nsin30∘−F=ma --------------(i) 2F−Ncos60∘=ma -----------------------(ii)
Equation (i) & (ii)
N2−F=2F−N2
N = 3F
So normal between the blocks = 3F